Calculate the Magnetic field induction at the centre of a coil bent in the form of square of side 10cm - Physics - Moving Charges And Magnetism

Question

Calculate the Magnetic field induction at the centre of a coil
bent in the form of square of side 10cm carrying current of 10A

Neha Gupta · Accepted Answer

Perpendicular distance of the side of the sqaure from the centre is 10/2 = 5 cm=0
05 msince direction of current is same in all sides, therefore net magnetic field will be added upB = 4×μ0I4πrsin 45 - sin(-45))B =  4×μ0I22πrB = 1
414×4π10-7×100 05πB = 113
12×10-6 tesla

Calculate the Magnetic field induction at the centre of a coil bent in the form of square of side 10cm carrying current of 10A.