calculate the emf of the following cell is found to be 0 20V at 298K cd|cd2+|| Ni2+(2 0M)|Ni what is - Chemistry - Electrochemistry

Question

calculate the emf of the following cell is found to be 0 20V at
298K cd|cd2+|| Ni2+(2 0M)|Ni what is the molar concentration of
cd2+ ions in the solution

Vartika Jain · Accepted Answer

Dear Student,

The cell reaction isCd(s) + Ni2+(aq) → Cd2+(aq) + Ni(s)and, Ecell=E°cell+0
0591nlog[Ni2+][Cd2+][Ni2+]=2n=2Here, E°cell=E°Ni2+/Ni-E°Cd2+/Cd=-0
25-(-0 40)=0 15 VEcell=0 20 VTherefore, 0 20=0
15 +0 05912log2[Cd2+]     0 05=0
05912log 2[Cd2+]or, log2[Cd2+]=1
69or, log 2- log[Cd2+] =1
69or, log [Cd2+]=log 2-1 69 =-1 39or
 [Cd2+]=Antilog(-1 39)=0 0407 M

calculate the emf of the following cell is found to be 0.20V at 298K cd|cd2+|| Ni2+(2.0M)|Ni what is the molar concentration of cd2+ ions in the solution.