calculate the distance between Na+ and Cl- ions in NaCl crystal if its density is 2.165 gcm-3 (molar mass of NaCl = 58.5gmol-1 NA = 6.02 x 10 23 mol-1)

For NaCl

M = 58.44g, z=4, d=2.165 g/cm3

Substituting the values in ..

d = (Z.M)/a3 NA

a= 5.64 x 10-8 cm

Na+ ion is present at edge center, therefore:



R+ is radius of sodium ion

R- is radius of chloride ion


(R++R-) is interionic distance.

(R++R-) =2.82x 10-8 cm

  • 10
What are you looking for?