atoms of the element B form hcp lattice and those of element A occupy 2by3rd part of tetrahydral voids what is the formula of the compound formed by the element A and B
In hcp lattice,
the no. of tetrahedral voids formed is equal to twice the no. of atoms of element which forms the lattice.
i.e. Tetrahedral voids = 2N (No. of atoms of B)
Now, as element A occupies only 2/3rd part of the void for each atom of B
so the no. of atoms of A present in tetrahedral void = 2 x 2/3 = 4/3
Hence ratio of A:B = 4/3 :1 = 4:3
Hence formula = A4B3