At temperature T, a compound AB2 (g) diassociates according to the reaction :

2AB2(g) [reverisble sign ] 2AB(g) + B2.

with degree of dissociation, x, which is small compared to unity. Deduce the expression for x in terms of equillibrium constant Kp and the total pressure.

The answer to your question is as follows:
                           2AB2 (g) ↔ 2AB (g) + B2(g)
Initially  pi                  0               0
At equ  pi-2x             2x             x


Therefore P (Total pressure) = pi + x or x= p-pi

Now Kp = p(B2) p (AB)2/(pAB2)2 

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