Area of triangle with vertices (k,0), (1,1) and (0,3) is 5 unit. Find the value(s) of k.

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Area of triangle with vertices (k,0), (1,1) and (0,3) is 5 unit
Find the value(s) of k

Gursheen Kaur · Accepted Answer

Dear Student,Solution) Given:- Area of triangle ABC = 5 sq unitsand veritces are=(k,0) (1,1)  and  (0,3)Now, Area of triangle = 12x1y2-y3+x2y3-y1+x3y1-y25=12k(1-3)+1(3-0)+0(0-1)10=-2k+310=±-2k+3 10=-2k+3                                                     10=-(-2k+3)10-3=-2k                                                       10=2k-37=-2k                                                               13=2k ⇒k=6
5or k=-3 5Regards!