arccos x+arccos 2x+arccos 3x =pi.if x satisfies cubic equation ax^3+bx^2+cx-1=0. then value of a+b+c =

Deare Student, 

cos–1 a + cos–1 b + cos–1 c = π


So here a = x, b = 2x, c = 3x 
x2+4x2+9x2= 1-12x312x3+14x2-1=0 or 12x3+14x2+0x-1=0 Comparing it with ax3+bx2+cx-1=0a = 12, b = 14 , c = 0 So a+b+c= 26Regards

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