Apurva is riding his motorcycle at a uniform speed of 54 km/h. He applies the breaks and the bike takes five seconds before coming to rest. The total mass of the motorcycle and its rider is 200 kg.

What is the force exerted by the breaks?

Solution
u = 54 km/h =15 m/st =  5sv = 0a =v-ut =0-155 = -3 m/s2m = 200 kgF = ma = 200×(-3) = -600 N   (in opposite direction of motion)

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