answer plz fast

Solution
According to Newton's law of law of gravitational force of gravitational is inversely proportional to the square of distance between the bodies so distance is doubled force of gravitational will reduce by 1/4.
$$\begin{gathered} F= G\frac{m_1{m}_2}{R^2} \\ Where R is the diatnce between the bodies . So , if R \prime =2R , then \\ F\text{'}= G\frac{m_1{m}_2}{{\left(2R\right)}^2} =\frac{1}{4} G\frac{m_1{m}_2}{R^2} =\frac{1}{4} F \end{gathered}$$