angle CPD = angle BPD and AD is the bisector of angle BAC . prove that triangle CAP congruent to triangle BAP and hence CP=BP

 for s CAP and BAPAP=PA ( common side)BAP=CAP ( as ADis the angle bisector  BAC )BPA=CPA (as we have given BPD=CPD , BPA=180°-BPD and CPA=180°-CPD)hence CAP congruent to BAPCP=BP (CPCT)

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