An Oil Drop of mass 0 03 gram carrying a negative charge of 3e is held in equilibrium between two - Physics - Electrostatic Potential And Capacitance

Question

An Oil Drop of mass 0 03 gram carrying a negative charge of 3e is
held in equilibrium between two metal plates 1 5 CM apart and
across which PD is maintained what is the intensity of electric
field and PD between the plate Given : e=1 6x10^-19, g= 9 8m/s

Shobhit Mittal · Accepted Answer

Dear Student,

m=0 03 gm , q=-3e, d=1
5 cm , let the field be E qE=mg3*1
6*10-19*E=0 03*10-3*9 8E=0 03*10-3*9 83*1 6*10-19=6
125*1014 N/CPD=E*1 5*10-2=6 125*1014 *1 5*10-2=9
1875*1012 V Regards

An Oil Drop of mass 0.03 gram carrying a negative charge of 3e is held in equilibrium between two metal plates 1.5 CM apart and across which PD is maintained what is the intensity of electric field and PD between the plate . Given : e=1.6x10^-19, g= 9.8m/s