An ester is boiled with KOH. The product is cooled and acidified with concentrated HCl. a white crystalline acid separates. The ester is
a) methyl acetate
b) ethyl acetate
c) ethyl formate 
d) ethyl benzoate

Dear Student,

Lets analyse the given option for the correct answer,

1. Methyl actetate on hydrolysis gives acetic acid in liquid state
2. Ethyl acetate on hydrolysis gives acetic acid in liquid state
3. Ethyl formate on hydrolysis gives formic acid in liquid state
4. Ethyl benzoate on hydrolysis gives benzoic acid in solid state

So it clear white crystalline product forms from ethyl benzoate, hence the answer is Option (D) Ethyl Benzoate.

Regards.

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