An elevator descends into a mine shaft at the rate of 6m/min .If the descent starts from 10m above ground level, how long will it take to reach -350 m .
elevator is 10m above the ground level.
it has to reach -350m.
so total vertical distance is =10+ 350=360
speed is 6m/min
so it will take =360/6=60 mins or 1 hour to cover the distance