A b o d y r o l l s d o w n a s l o p e f r o m a h e i g h t o f 100 m . I t ' s v e l o c i t y a t t h e f o o t o f t h e s l o p e 20 m s - 1 . W h a t p e r c e n t a g e o f i t s i n i t i a l p o t e n t i a l e n e r g y i s c o n v e r t e d i n t o k i n e t i c e n e r g y ? [ g = 10 m s - 2 ] Share with your friends Share 0 Shobhit Mittal answered this Dear Student,KE at the foot is K=mv22=400m2=200mPE =mgh=1000m.the percentage that convert into KE=200m1000m*100=20 percent.Regards 0 View Full Answer