abcd is a rectangle the perpendicular dn from d on ac divides angle d in the ratio 2:3.find ndb

Given, ABCD is a rectangle. The perpendicular DN from D on AC divides angle D in the ratio 2:3.

angle ADC = 90 degree

as, it is given that, the perpendicular DN from D on AC divides angle D in the ratio 2:3.

divide the 90 degree angle into the ratio  2:3.

2x+3x = 90 

5x = 90

x= 18 degree

therefore, 2x = 2*18 = 36degree and 3x= 3*18=54degree

now, angle ADN = 36 degree and 

angle NDC = 54 degree= angle NDB + angle BDC

  • 3

2x+3x=180[sum of angles]

5x=180

x=1805

x=36

  • -5
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