abcd is a rectangle the perpendicular dn from d on ac divides angle d in the ratio 2:3.find ndb
Given, ABCD is a rectangle. The perpendicular DN from D on AC divides angle D in the ratio 2:3.
angle ADC = 90 degree
as, it is given that, the perpendicular DN from D on AC divides angle D in the ratio 2:3.
divide the 90 degree angle into the ratio 2:3.
2x+3x = 90
5x = 90
x= 18 degree
therefore, 2x = 2*18 = 36degree and 3x= 3*18=54degree
now, angle ADN = 36 degree and
angle NDC = 54 degree= angle NDB + angle BDC