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ABCD is a cyclic quadrilateral with O as centre of the circle.if m angleBOD =136,find m angle BCD?

The angle at the centre of a circle is twice the angle on the circle subtended by the same arc

so,

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 136/2 = 68 since the 

The angle subtended by an arc at the centre of a circle is double the angle subtended by it at any point on the remaining part of the circle.


This case uses the converse of the above theorem.

 

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