Aarav is 3 years younger than his sister keya. if the sum of their ages is 27 years, what are the present ages?
Let Keya's age be x
then aarav's age will be x-3
sum of their ages =27
=x+(x-3)=27
=x+x-3=27
=2x-3=27
=2x=27+3
=2x=30
=x=30/2
=x=15
therefore Keya is 15 years old
Aarav's age=x-3
=15-3
=12
then aarav's age will be x-3
sum of their ages =27
=x+(x-3)=27
=x+x-3=27
=2x-3=27
=2x=27+3
=2x=30
=x=30/2
=x=15
therefore Keya is 15 years old
Aarav's age=x-3
=15-3
=12