A thin bar magnet is cut into two equal parts.the ratio of moment of inertia to the magnetic moment of each part will become?(as compare to original magnet)
solution please.
options-1) 1/2
2)1/4
3)1/8
4)1

14 
I guess
  • -25
how it comes out to be 1/4 ?will you explain?
  • 2
How is it coming.Please merination experts help out with its process.
  • -10
This is the sol

  • 21
Hope it will clear your doubts

  • -4
Hope this will help you

  • 80
The answer is 1/2 but how?
  • -17
so 1/4
 
  • -7

When the magnet is not cut from the between into two equal parts as shown in figure above.
Let LL be the length of the magnet and MM be the magnetic moment of the magnet.
Let pole strength be SS and mm be the mass of the magnet.
According to given data,
Initial moment of inertia =mL2=mL2
Thus, initial magnetic moment =S×2L=S×2L
Their ratios =mL2S=mL2S …….. (1)(1)
After cutting the magnet pole strength remains the same.
Thus, final moment of inertia =m2(L2)2=mL28=m2(L2)2=mL28
Magnetic moment =S×2(L2)=S×L=S×2(L2)=S×L
Now, their ratios are given by =mL8S=mL8S ……. (2)(2)
For the ratios of magnetic moment we have
Ratios of (1)(1) and (2)(2) =mL8SmL2S=14=mL8SmL2S=14
Thus magnetic moment of each part will become 1:4
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