a stone is projected from point a with speed u making an angle 60 degrees with the horizontal.the fixed inclined surface makes an angle 30 degrees with the horizontal.the stone lands at b after time t.then the distance ab=

Dear Student,

Please find below the solution to the asked query:

Consider the situation as shown in the figure below.

Let a particle be projected up with a speed u from an inclined plane which makes an angle α with the horizontal velocity of projection makes an angle θ with the inclined plane.

The equation for the range on an inclined plane is,

R=2u2gsin θ cos θ+αcos2 α

Now according to the given information in the question,

α=300 andangle of projection with respect to horizontal isθ+α=600θ=300

Therefore, the range on the inclined plane. In the given question ab is,

R=2u2gsin θ cos θ+αcos2 α=2u2gsin 300 cos 600cos2 300R=2u2g1212322=2u2g1434=2u2g13R=2u23g


Hope this information will clear your doubts about the topic.

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