A spring of mass m lies on a smooth table One end of it is sclamped to the vertical - Physics - Systems of Particles and Rotational Motion

Question

​A spring of mass m lies on a smooth table One end of it is
sclamped to the vertical wall and the other end is attached to a
mass m and is placed on a horizontal frictionless surface If the
Block of mass M is given a velocity V towards right, find the KE of
the system

Saroj Jain · Accepted Answer

Dear Student,

I can assume that the mass of the spring and block is
same

Since the velocity of the spring is zero and the velocity of the
block(m) is V

Velocity of the Center 
of the mass of the system is:
Vcm = m×v + m×0m + m= v2K
E of the system = 12×Masssystem ×V2cm= 12×2m ×(v2)2= mv24 Ans

Regards

​A spring of mass m lies on a smooth table. One end of it is sclamped to the vertical wall and the other end is attached to a mass m and is placed on a horizontal frictionless surface. If the Block of mass M is given a velocity V towards right, find the KE of the system

A spring of mass m lies on a smooth table. One end of it is sclamped to the vertical wall and the other end is attached to a mass m and is placed on a horizontal frictionless surface. If the Block of mass M is given a velocity V towards right, find the KE of the system