A solution of 8% boric acid is to be diluted by adding a 2% boric acid solution to it - Maths - Linear Inequalities

Question

A solution of 8% boric acid is to be diluted by adding a 2% boric
acid solution to it The resulting mixture is to be more than 4% but
less than 6% boric acid If we have 640 litres of the 8% solution
how many litres of the 2% solution will be added?

(i) Find lower limit

(ii) Find upper limit

Atul Shaw · Accepted Answer

Solution:Initial Volume=640LIt was 8% boric acid solution
Let the added volume be x L
 It was 2% boric acid solution 1
 For lower limit, volume of mixture should be added less
 If less volume is added then concetration will decrease less
Thus, % should be 6%6%=8% of 640+2% of x640+x⇒6% of 640+6% of x=8% of 640+2% of x⇒4% of x=2% of 640⇒x=2% of 6404%=320L2
 For higher limit, volume of mixture should be added high
If less volume is added then concetration will decrease more
Thus, % should be 4%⇒4%=8% of 640+2% of x640+x⇒4% of 640+4% of x=8% of 640+2% of x2% of x=4% of 640x=4% of 6402%=1280L

A solution of 8% boric acid is to be diluted by adding a 2% boric acid solution to it. The resulting mixture is to be more than 4% but less than 6% boric acid. If we have 640 litres of the 8% solution how many litres of the 2% solution will be added? (i) Find lower limit (ii) Find upper limit.

A solution of 8% boric acid is to be diluted by adding a 2% boric acid solution to it. The resulting mixture is to be more than 4% but less than 6% boric acid. If we have 640 litres of the 8% solution how many litres of the 2% solution will be added?

(i) Find lower limit

(ii) Find upper limit.