# A shopkeeper bought some sweets at 11 for a rupee. He bought an equal number of sweets at 10 for a rupee.He sold all the sweets at 8 for a rupee. Find his gain or loss per cent.

A shopkeeper bought some sweets at 11 for a rupee. He bought an equal number of sweets at 10 for a rupee.He sold all the sweets at 8 for a rupee. Find his gain or loss percent.

Cost price of 11+10=21 sweets is 1+1=Rs.2

So, cost price of each sweet=Rs. 2/21

Selling price of 8 sweets = Rs.1

Selling price of 1 sweet=Rs.1/8

Gain = 1/8 - 2/21=(21-16)/168=5/168 • 3

COST OF 11 SWEETS BOUGHT BY THE SHOPKEEPER =1 Rs

COST OF 10 SWEETS BOUGHT BY THE SHOPKEEPER =1 Rs

TOTAL COST OF 11+10 SWEETS BOUGHT BY THE SHOPKEEPER=1+1 =2 Rs

COST OF 1 SWEET BOUGHT BY THE SHOPKEEPER= 2/21Rs

COST OF 8 SWEETS SOLD BY THE SHOPKEEPER=1Rs

COST OF 1 SWEET SOLD BY THE SHOPKEEPER=1/8Rs

COST PRICE=2/21Rs

SELLING PRICE=1/8Rs

CHECKING WHETHER IT IS A PROFIT OR LOSS.

2/21 , 1/8

LCM OF 21 , 8 IS 168

16/168 , 21/168

SO , SP IS GREATER THAN CP HENCE IT IS PROFIT.

PROFIT=SP-CP

=21/168-16/168

=5/168

PROFIT%=P/CPx100

=5/168 / 1/21x 100

=5/168 x 21/1 x 100

500/16 = 125/4%

ANS P=5/168

=125/4%

• 1
What are you looking for?