A railway track running north-south direction has 2 parallel rails 1m apart .Calculate the value of induced emf between rails when a train passes at a speed of 90km/hr .BH=.0.3*10-4Wbm-2 and angle of dip is 60.

guess the answer is 15*pow(10,-4) V = value of induced emf 

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200
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Good
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V. Good
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Railway track running notes South has two parallels 1.0 M apart calculate the value of induced EMF between the rails when a train passes at a speed of 90 km per hour horizontal component of Earth's failed at that place is 0.3 x minus 4 per metre square and angle of dip is 60 degree

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Railway track running north south has two parallels 1.0 M apart calculate the value of induced EMF between the rails when a train passes at a speed of 90 km per hour horizontal component of Earth's field at that place is 0.3 multiplied and minus 4 Weber per metre square and angle of dip is 60 degree
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E- 1.3? 10^-3V
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Give me solution pls
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Please find this answer

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Ans. 1.6×10^-3

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