A projectile is thrown horizontallyfrom the top of a tower & strikes the ground after 3 sec at an angle of 45 deg with the horizontal. Find the height of the tower & the speed with which the body was projected. Given g = 9.8 m/see2.

height is given by:h = ut +12at2where u is the initial velocity in vertical direction.u =0h = 0+0.5×10×9 = 45 mpotential energy at the height 45 m = kinetic energy at the groundmgh = 12mv2v = 2gh = 2×10×45 =30 m/s

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