a projectile is fired horizontal with a speed 98m/s from the top of hill 490m height. find

velocity in which it strikes the gournd .

time taken to reach the gournd.

distance of the target from the hill.

Question

a projectile is fired horizontal with a speed 98m/s from the top
of hill 490m height find

velocity in which it strikes the gournd
time taken to reach the gournd
distance of the target from the hill

Neha Gupta · Accepted Answer

Initial speed in horizontal direction ux = 98 m/stime taken to reach the ground is tinitial velocity in vertical direction uy = 0height = 490 mdistance travelled in vertical direction is equal to heighth = uyt + 12gt2490 = 0+0
5×9
8t2t = 10 sFinal velocity in vertical directionvy = uy + gt= 0+9
8×10 = 98 m/sthere is no acceleration in x direction , then vx = uxNet velocity when when projectile reaches teh ground
V= vx2+vy2 = 982+982 = 982 m/sDistance travelled in horizonatl direction s = uxt = 98×10 = 980 m

a projectile is fired horizontal with a speed 98m/s from the top of hill 490m height. find velocity in which it strikes the gournd . time taken to reach the gournd. distance of the target from the hill.

a projectile is fired horizontal with a speed 98m/s from the top of hill 490m height. find

velocity in which it strikes the gournd .

time taken to reach the gournd.

distance of the target from the hill.