A potentiometer wire of length 5m has resistance of 9r. It is connected to a cell of emf 1V and internal resistance of 0.5r. The length of the balance point for a cell of emf 0.5 V will be

Dear Student,

l=5 mR=9rE=1 VoltR1=0.5rE0=0.5 VoltI=ER+R1=19r+0.5r=19.5r AV=IRV=19.5r×9r=0.94 VoltVl=0.945=0.188 V/mE0=Vl×x0.5=0.188xx=0.50.188=2.65 m

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