A point moves in a straight line so that its distance from the start in time t is equal to s=1/4t^4-4t^3+16t^2 find:
a) At what times was the point at its starting position?
b) At what times its velocity equal to zero?
Dear Student,
Please find below the solution to the asked query:
The distance travelled by the particle varies with time as,
So, if the particle should be at the starting point. Then,
The velocity of the particle is,
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