a number X is selected at random from the numbers 1,4,9,16 and another number y is selected at random from the numbers 1,2,3,4. find the probability that the value of xy is more than 16. Share with your friends Share 14 Mallika Anand answered this No. of possible outcomes = 8Total number of outcomes = 4*4 = 16P(A) = 8/16 = 1/2 -11 View Full Answer Mallika Anand answered this I am sorry... this answer was for product less than 16 1 Mallika Anand answered this No. of possible outcomes = 6Total no. of outcomes = 4*4 = 16P(A) = 6/16 = 3/8 18 Aiymenlatheef answered this i dont think this answer is correct -2 Ashutosh Mehra answered this Plzzzz give me a correct answer.. . 1 Zannu answered this Are repeated outcomes considered???or eXcluded??? 5 Neha answered this is it -4 Siddharth answered this The answer is 9/16 not 8/16 or 6/16 -5 Sweetie answered this 8/16 = 1/2 7 Palak Singh answered this Hope this helps! 6 Dibyasree Sanyal answered this This is the answer~ 1 Dibyasree Sanyal answered this This is the answer~ -1 Khushi answered this The correct answer is 3 by 8 because it is given that the value should be greater than 16 not equal to 16 so correct answer is 3 by 8 not 1 by 2 0
