A number of two digits exceed four times the sum of its digits by 6 and it is increased by 9 on reversing its digits. Find the number
let the unit digit of the number be x and ten's digit be y.
the number = 10y+x
10 y+x = 4(x+y) + 6
10 y + x - 4x - 4y = 6
- 3x +6y = 6
- x + 2y = 2...............(1)
the number by reversing its digit = 10 x + y
10y+x = 10x+y + 9
-9x + 9y = 9
-x + y = 1.........(2)
subtracting eq (2) from eq(1):
y = 1 and x = 0
thus the number is 10.
hope this helps you.