a number consist of two digits of which the tens digit exceeds the unit digit by 6.the number itself is equal to tens times the sum of its.find the num.

let unit digit be x 

tens digit =x+6

value of no.

10(x+6)+x

10x+60+x

11x+60

ten times sum of digits=10(x+x+6)

10(2x+6)

20x+60

according to question 

20x+60=11x+60

20x-11x=60-60

9x=0

x=0/9=0

therefore unit digit = 0

tens digit=0+6

therefore no. =60

  • 11

LET Y (UNITS DIGIT) PLUS 6 EQUAL THE TENS DIGIT X
Y=X-6
10(X+Y)=10X+Y REPLACE Y WITH (X-6)
10(X+X-6)=10X+(X-6)
10(2X-6)=10X+X-6
20X-60=11X-6
20X-11X=60-6
9X=54
 
 

X=54/9
X=6 WHICH IS THE TENS DIGIT
Y=6-6=0 FOR THE UNITS DIGIT'
PROOF
10(6+0)=10*6+0
60=60 

  • 0
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