a force F=(3x^2yicap +x^3jcap) is acting on a particle find work done by the force during displacement of the - Physics - Work Energy And Power

Question

a force F=(3x^2yicap +x^3jcap) is acting on a particle find work
done by the force during displacement of the particle from (1m,1m)
to (2m,-1m)

Sanjay Upadhyay · Accepted Answer

Dear studentGiven F=3x2yi^+x3j^and points (1m, 1m) and (2m, -1m)now displacement ds=(i^+j^)-(2i^-j^)=-i^net workdone W=∫F
dsW=∫123x2y  dxW=8y-y=7yregards

a force F=(3x^2yicap +x^3jcap) is acting on a particle. find work done by the force during displacement of the particle from (1m,1m) to (2m,-1m)