A cylindrical vessel of cross - section A contains water to a height h.There is a hole in the bottom of radius ' a ' .The time in which it will be emptied is : Share with your friends Share 5 Sanjay Singh answered this Dear student Let at certain instant of time level of liquid is at a height of x above orifice.Volume of liquid coming out from the orifice =(2gx)×(πa2)volume of liquid descending per second =A×(-dxdt)equating both the volume(2gx)×(πa2)=A×(-dxdt)A∫h0dxx=(πa2) 2g∫0tdt2A×(x)0h=2g×(πa2)×t2A×(x)0h=2g×(πa2)×t2A×(h)=2g×(πa2)×tt=2A(πa2)×h2gt=A(πa2)×2hgRegards 21 View Full Answer M. Nivesh answered this time taken is A/a(h/2g)1/2 -1 Pulkit answered this a/a(h/2g)1/2 -2
