A cyclic process contains four steps AB, BC,CD and DA. Heat involved in different processes is given as 
QAB= +200J , QBC= +600J , QCB = -300J , QDA= 0.
The efficiency of process is
(1) 5/8         (2) 3/8         (3) 1/4        (4) 1/2

Dear student
heat energy absorbed is positive sign and heat energy rejected is with negative sign.

Regards
 

  • 1
n =1-q1/q2

then we
have n=1-800/300=5/8
  • 2
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