A container contains 16 g of oxygen ,24g of methane ,96g of ozone and 80 g of so3 and the temp is 227 degree celcius volume is 10L and R is0.08 so calculate the mole fraction and partial pressure of each gas
Dear student
For this question first of all you need to calculate the number of moles of all the components in the container.
The number of moles are :
oxygen 0.5 mol
methane 0.67 mol
ozone 2 mol
sulphur trioxide 1 mol
The temperature of the reaction mixture is 500K
R = 0.08
So the total number of moles are: 4.167 mol
Using PV = nRT
The total pressure can be calculated as
P = 10.668 atm
Now to calculate the mole fraction and the partial pressure use the formula
The same formula can be used for others also.
Regards
For this question first of all you need to calculate the number of moles of all the components in the container.
The number of moles are :
oxygen 0.5 mol
methane 0.67 mol
ozone 2 mol
sulphur trioxide 1 mol
The temperature of the reaction mixture is 500K
R = 0.08
So the total number of moles are: 4.167 mol
Using PV = nRT
The total pressure can be calculated as
P = 10.668 atm
Now to calculate the mole fraction and the partial pressure use the formula
The same formula can be used for others also.
Regards