A constant current was passed through a solution of AuCl4 between gold electodes. After a period of 14 min the cathode recorded an increase in mass of 1.808 get. Calculate the quantity of current passed in solution. What was the magnitude of current. ( atomic mass of gold = 197 )

The solution is as follows:


m =MnF×Q1.808 = 1973×96500×Q  Q = 3013.3 C   Q = It    I=Qt=3013.314×60=3.58 amp

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