A circular coil of 500 turns has a radius of 2 m, and carries a current of 2 A. What is the magnetic field at a point on the axis of the coil at a distance equal to radius of the coil from the center?
B= (µ0 n I r²)/(2(x²+r²)³/²
n= 500 r=x=2m I=2A
B=(4π × 10-7 × 500 × r²)/(2(2r²)³/²)
B=(4 × 3.14 × 500)/(2 × 2√2 × 2)
B=1.11 × 10-⁴ T