a bride over a canal is in the form of a circular arc of radius 5m. the max speed with which a motor cycle crosses the bridge without leaving the round at the highest point is? ( = 10ms^-1) (ans : 5root2)

Dear Student,

Please find below the solution to the asked query:

Let the maximum speed of the motor cycle, with which it can go on bridge without loosing the contact is V. Then, at the highest point on the bridge, the weight of the motor cycle should be equal to the centrifugal force on the motor cycle. Therefore,

$$\begin{gathered} \frac{m{V}^2}{R}=mg \Rightarrow V=\sqrt{Rg}=\sqrt{5\times 10} \Rightarrow V=\sqrt{50} \\ \Rightarrow V=5\sqrt{2} \raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right. \end{gathered}$$

 

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