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a bride over a canal is in the form of a circular arc of radius 5m. the max speed with which a motor cycle crosses the bridge without leaving the round at the highest point is? ( = 10ms^{-1}) (ans : 5root2)

Dear Student,

Please find below the solution to the asked query:

Let the maximum speed of the motor cycle, with which it can go on bridge without loosing the contact is *V*. Then, at the highest point on the bridge, the weight of the motor cycle should be equal to the centrifugal force on the motor cycle. Therefore,

$\frac{m{V}^{2}}{R}=mg\Rightarrow V=\sqrt{Rg}=\sqrt{5\times 10}\Rightarrow V=\sqrt{50}\phantom{\rule{0ex}{0ex}}\Rightarrow V=5\sqrt{2}\raisebox{1ex}{$m$}\!\left/ \!\raisebox{-1ex}{$s$}\right.$

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