# a box full of black and white balls has 95 black balls.if 8/27 of all balls in the box are white balls,how many balls are there in the box?

$Letthetotalballsinboxbex.\phantom{\rule{0ex}{0ex}}Thenwhiteballs=\frac{8}{27}x\phantom{\rule{0ex}{0ex}}andblackballs=95.\phantom{\rule{0ex}{0ex}}ATQ\phantom{\rule{0ex}{0ex}}95+\frac{8}{27}x=x\phantom{\rule{0ex}{0ex}}\Rightarrow 95=x-\frac{8}{27}x\phantom{\rule{0ex}{0ex}}\Rightarrow 95=\frac{27x-8x}{27}\phantom{\rule{0ex}{0ex}}\Rightarrow 95=\frac{19x}{27}\phantom{\rule{0ex}{0ex}}\Rightarrow x=\frac{95\times 27}{19}\phantom{\rule{0ex}{0ex}}\Rightarrow x=135\phantom{\rule{0ex}{0ex}}So,totalballsare135.$

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