a body thrown vertically up with initial velocity 52 m/sec from the ground passes twice a point at H height above at an interval of 10 s . The height H is (Take g= 10)

u = 52 m/s
s = ut + 12gt2
s = 520 + 12(-10)(10)2
s = 520 - (5)(10)2
s = 520 - 500 = 20 m
Given that
s = 2H
2H =20 m
H = 10 m
 

  • 36

s=ut-1/2*gt2

s=52*10- 5(10)2

s=520-500

s=20m

As it passes twice a point at H height.

i.e 2H = 20m

H=10m

IF I AM RIGHT THUMBS UP BUDDY

  • 28
What are you looking for?