a block of mass 2 kg rests on a rough inclined plane making an angle 30degrees with the horizontal . the coeffecient of static friction between the block and the plane is 0.7 . the frictional force on the block is??

Given, m = 2 kg
θ = 300
μ = 0.7

As it is clear for figure :
R = m g cos ​θ
Therefore, force of friction, F = ​μ R = ​μ m g cos ​θ = 0.7 X 2 X 9.8 X cos 300 = 11.86 N

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