# A block of mass 10 kg is released on rough incline plane inclined at an angle 30 degree. Block start descending with acceleration 2 m/s² . Kinetic friction force acting on block is ( take g= 10m/s² )

g = 10 m/sec

^{2}

θ = 30

a = 2m/sec

^{2}

f = ??

formula => f = m g sin (theta) - ma

substituting the required ,

f = 10 * 10 * sin (30) - 10 * 2

= 100 * 1/2 - 20

= 50 - 20

= 30 kg m/sec

^{2}