A block of mass 10 kg is released on rough incline plane inclined at an angle 30 degree. Block start descending with acceleration 2 m/s² . Kinetic friction force acting on block is ( take g= 10m/s² )
m= 10 kg
g = 10 m/sec2
θ = 30
a = 2m/sec2
f = ??
formula => f = m g sin (theta) - ma
substituting the required ,
f = 10 * 10 * sin (30) - 10 * 2
= 100 * 1/2 - 20
= 50 - 20
= 30 kg m/sec2
g = 10 m/sec2
θ = 30
a = 2m/sec2
f = ??
formula => f = m g sin (theta) - ma
substituting the required ,
f = 10 * 10 * sin (30) - 10 * 2
= 100 * 1/2 - 20
= 50 - 20
= 30 kg m/sec2