a ball is dropped from the top of a building if it covers second half of a building in 1 second. Find out height of the building

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let the height be H let the velocity at second half be u H2=u+g2u2=gHu=gHH2=gH+g2H=2gH+gsolve the above eqn to get H put g=10 m/s2regards

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A ball is projected vertically upwards from the ground at 40m/s. Find out time and speed of the ball, when it will be 20 m below its highest height
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