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(a+b) 2 x2 + 8(a2 - b2) x +16 (a-b)2 = 0

solve for x.

please answer this......

  • 8
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D = b2- 4ac

here, D = 64(a2 - b2)2 - 4(a+b)2*16(a - b)2

= 64(a4 +b4 -2a2b2) - 64(a4 + a2b2- 2a3b + a2b2 +b4 -2ab3 +2a3b +2ab3-4a2b2)

=64 (a4 +b4- 2a2b2 - a4 -b4 + 2a2b2 )

=0

since D= 0 roots are real and equal

X = (-b +√D)/2a

now you know the values of a, b & D you can find X

  • 33

 Here X = (-8(a2- b2)+ 0 ) / 2 (a+ b)2 and other value is (-8(a2- b2) - 0 ) / 2 (a+ b)2

now you may simplify these values.

If this helps please give a thumbs up

  • 4

thanks but can you solve further

  • -5

thaks for this information.But value for x=-4(a-b)/a+b

  • 16
thx
  • -8
D=0 then put values;in the formula
  • 7
Describe in deep reproduction
  • -10
This is the correct answer Solve with D=b^2-4ac

  • 20
This is the ans hope it helps u guys

  • -4
Since D=0...So both the value of x will be equal

  • 6
can someone solve it with factorisation method?
  • -1
Beehaan choood question
  • -1

  • (a +b)^2 x ^2 +8(a^2 – b ^2 )x +16(a – b)^2 = 0  Pls help
     

  • 0
Wait. Shouldn't the answer be 4(b-a) /a+b ??
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