a and b are two sets such that

n(a-b)=20+x

n(b-a)=3x

n(ab) =x+1 if n(a)= n(b)

the value of x

n(a-b)=20+x

n(b-a)=3x

n(ab) =x+1

We know that

n(a-b) = n(a)-n(ab)

∴n(a) = n(a-b) + n(ab)

 = (20+x) + (x + 1)

 = 2x + 21

Similarly, n(b) = n(b-a) + n(ab)

 =3x + (x+1)

 =4x + 1

According to the question,

n(a) = n(b)

∴2x + 21 = 4x  +1

⇒2x = 20

x = 10

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