A 80uF capacitor is charged by a 50V battery The capacitor is disconnected from the battery and then connected across - Physics - Current Electricity

Question

A 80uF capacitor is charged by a 50V battery The capacitor is
disconnected from the battery and then connected across another
uncharged 320 uF capacitor Calcuulate the charge on the second
capacitor

A K Daya Sir · Accepted Answer

Q1 = charge on first capacitor = C1
V1 = 80u x 50 = 4000u C = 4mC
common potential after connecting them together
V = total charge / sum of capacitances
= (Q1 + Q2) / C1 +
C2 = 4 x 10-3 / (80 + 320) x 10-6
= (4/400) x 103 = 1000/100 = 10 V
charge on second capacitor = C2 V = 320u x 10 = 3200u
C = 3 2 m C

A 80uF capacitor is charged by a 50V battery.The capacitor is disconnected from the battery and then connected across another uncharged 320 uF capacitor. Calcuulate the charge on the second capacitor.