A (1,4) B(-1,2) and C(5,-2) are the vertices of a triangle ABC. Find the coordinate of the point where the right bisector of BC intersects the median through C

Hi,


mid point of AB = 1-12,4+22= 0,3So equation of CE, y-3= -2-35-0x-0x+y-3=0.....1Now coordinate of M =  5-12,-2+22= 2,0Slope of BC = -2-25+1= -23so slope of perpendicular line = 32so equation of perpendicular line y-0 = 32x-23x-2y-6=0.....2Now solve equation 1 and 2 to get the required point. Regards

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