# A={1,3,5}; B= {9,11} R = {(a,b) belongs to AxB:a-b is odd} Write the relation R

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@ KWXYZ.

WHEN U WILL find the A*B element then the element will be like this..

(1,9) (1,11) (3,9) (3,11) (5,9) (5,11)

So, as per the condition of relation R (a-b) will belongs to a*b set and also its odd..

s0,,

1-9=-8 which is even.
1-11=-10 which is even.
3-9=-6 which is even

3-11=-8 which is even

5-9=-4 which is even

5-11=-6 which is also even.
SO,THIS FORCE THE RELATION R SET TO BE A NULL SET WHICH DOES NOT CONTAIN ANY ELEMENT OR ORDERED PAIR..

HOPE IT HELPS..

CHEERS,

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