A={1,3,5}; B= {9,11} R = {(a,b) belongs to AxB:a-b is odd} Write the relation R

Given:-A=1,3,5,B=9,11R=a,bA×B:a-b is oddAs A×B=1,9,1,11,3,9,3,11,5,9,5,11For the elements of A×B , a-b is1-9=-8,1-11=-10,3-9=-6,3-11=-85-9=-4,5-11=-6As we can see that a-b is not odd for any element of A×B.So, relation R is a null set.R=.

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@ KWXYZ.

WHEN U WILL find the A*B element then the element will be like this..

(1,9) (1,11) (3,9) (3,11) (5,9) (5,11)

So, as per the condition of relation R (a-b) will belongs to a*b set and also its odd..

s0,,

1-9=-8 which is even.
1-11=-10 which is even.
3-9=-6 which is even

3-11=-8 which is even

5-9=-4 which is even

5-11=-6 which is also even.
SO,THIS FORCE THE RELATION R SET TO BE A NULL SET WHICH DOES NOT CONTAIN ANY ELEMENT OR ORDERED PAIR..

HOPE IT HELPS..

CHEERS,

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