64 - a³b³ +8 - 2ab

factorize it?

Use the identity a³ - b³ = (a - b) × (a² + b² + ab), equation becomes

= [(4 - ab) × (16 + a²b² + 4ab)] + [2 × (4 - ab)]

taking (4 - ab) common from the equation, we get

= (4 - ab) × [(16 + a²b² + 4ab) + 2]

= (4 - ab) × (a²b² + 4ab + 18)