50 0 kg of N2 (g) and 10 0 kg of H2 (g) are mixed to produce NH3 (g) - Chemistry - Some Basic Concepts of Chemistry

Question

50 0 kg of N2 (g) and 10 0 kg of H2 (g) are mixed to produce NH3
(g) Calculate the

NH3 (g) formed Identify the limitingreagent in the
production of NH3 in this situation

Neelam Yadav · Accepted Answer

Dear Student,
N2 + 3H2 ---------> 2NH3
Number of moles of N2 = 50kg X
1000g/1kgx1mole/28g
= 17 86 x 102 mol
Number of moles of H2 = 10kg x1000g/1kgx 1mol/2
016g
= 4 96 x 103 mol
According to the balanced reaction :
17 86 x 102 mol of N2 will react with =
3/1 x 17 86 x 102
= 5 36 x 103 mol
since number of moles of H2 are 4 96 x
103
Therefore dihydrogen is the limiting reagent

50.0 kg of N2 (g) and 10.0 kg of H2 (g) are mixed to produce NH3 (g). Calculate the NH3 (g) formed. Identify the limitingreagent in the production of NH3 in this situation

50.0 kg of N2 (g) and 10.0 kg of H2 (g) are mixed to produce NH3 (g). Calculate the

NH3 (g) formed. Identify the limitingreagent in the production of NH3 in this situation