5) The given figure shows two infinite lines of charge having equal (in magnitude) linear charge density but with opposite sign. The electric field at any point on x axis (for x > 0) is along the unit vector . ( A ) cos θ i ^ + sin θ j ^ ( B ) i ^ ( C ) j ^ ( D ) - sin θ i ^ + sin θ j ^ Share with your friends Share 15 Sanjay Singh answered this Dear student From the diagram as shown in the figure .Electric field due to positive and the negative charge are equal in magnitude and their directions are shown in the figure .From the figure component of electric field due to positive charge along X axis is =Ecos(90-θ)=Esinθsimilarly component of electric field due to negative charge is along negative X axis is and is equal to =Esinθso net electric field along X axis is zero.component of electric field due to positive charge along Y axis is =component of electric field due to negative charge along Y axis =EcosθSo net electric field is along positive direction of Y axis .so option is j^.Regards -11 View Full Answer